Ametal rod that is 4.00 m long and 0.500 cm^2 in cross-sectional area is found to stretch 0.200 cm under a tension of 5000 n . what is young's modulus for this metal?
y = pa ?

Young modulus,

Explanation:

Given that,

Length of the metal rod, l = 4 m

Area of cross section of the metal rod,

Change in length,

Tension, T = 5000 N

To find :

The Young modulus of this metal

Solution,

The formula for the Young modulus of the metal is given by :

So, the Young modulus of this metal is

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer