Atransverse wave is traveling on a string stretched along the horizontal x-axis. the equation for the
vertical displacement y of the string is given by y = 0.0020 cos[? (15x - 52t)], where all quantities are in
si units. the maximum speed of a particle of the string is closest to
a) 0.33 m/s.
b) 0.43 m/s.
c) 0.53 m/s.
d) 0.64 m/s.
e) 0.74 m/s.

A) 0.33 m/s

Explanation:

The standard form of a transverse wave is given by  

y = a  cos ( ω t − kx ) ,   k =  2 π  / λ

Amplitude,   a =  0.002  m

Wavenumber (k)=47.12 and wavelength  ( λ )  =  0.133 m

Time period(T)=0.0385 s and angular frequency  ( ω )  =  52 π  rad/s

Maximum speed of the string is given by  aw

Therefore ; max. speed = 0.002 x 52 π = 0.327 m/s

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.