Light of wavelength 588.0 nm illuminates a slit of width 0.68 mm. (a) at what distance from the slit should a screen be placed if the first minimum in the diffraction pattern is to be 0.89 mm from the central maximum? m (b) calculate the width of the central maximum. mm

(a) 1.029 m

(b) 1.78 mm

Solution:

As per the question:

Wavelength of light,

Slit width, w = 0.68 mm

Now,

The distance first minimum in the diffraction pattern,

Now,

(a) For first minima:

where

D = Distance from the screen

D = 1.029 m

(b) The width of the central maxima is given by:

2y =

report!

explanation:

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