Two vessels are labeled a and b. vessel a contains nh3 gas at 76°c, and vessel b contains ne gas at the same temperature. if the average kinetic energy of nh3 is 7.1 × 10−21 j/molecule at 70°c, calculate the root-mean-square speed of ne atoms in m/s.

For te Ne as

T=76°C=76+273=349K

molecular mass of Ne=20.18g/mol=0.02018kg/mol

R=8.314J/K.mol   ..the gas constant

using the formula

431355.69 j/kg

J=1kg/(kg)

[tex]\pi^2 _{rms}=m^2/s^2

[tex]\pi _{rms}=m/s

therefore, taking the square root of 431355.69 j/kg

[tex]\pi _{rms}=656.77m/s

answer; /// the above statement is (true);

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