Apackage is dropped from a helicopter moving upward at 15m/s. if it takes 16.0 s before the package strikes the ground, how high above the ground was the package when it was released?

Height of package initially = 1054.4 metre

Explanation:

The package is dropped from a helicopter moving upward at 15 m/s.

Total time taken for the package to reach the ground = 16 seconds.

Initially , the package has an upward velocity and therefore it moves upwards ,reaches the topmost point and then falls down and finally strikes the ground.

Displacement , h = unknown

Time , t = 16 seconds

Initial velocity , u = 16 m/s

By equation of motion ,

s =

Acceleration ,  a = g = 9.8 m/

-s =

-s = 240 - 1254.4

s = 1054.4 metres

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