Auniform ladder of length l rests against a smooth, vertical wall. if the coefficient of static friction is 0.50, and the ladder makes a 53⁰ angle with respect to the horizontal, how far along the length of the ladder can a 56.0-kg person climb before the ladder begins to slip? the ladder is 7.5 m in length and has a mass of 21 kg.

X = 5.44 m

Explanation:

First we can calculate the normal force acting from the floor to the ladder.

W₁+W₂ = N  

W1 is the weigh of the ladder

W2 is the weigh of the  person

So we have:

The friction force is:

Now let's define the conservation of torque about the foot of the ladder:

Solving this equation for X, we have:

Finally, X = 5.44 m

Hope it helps!

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explanation:

if they have a finite resultant