Asolenoid of length 0.700m having a circular cross-section of radius 5.00cm stores 6.00 μj of energy when a 0.400-a current runs through it.

what is the winding density of the solenoid? (μ0 = 4π*10-7 t*m/a)

a) 865 turns/m

b) 327 turns/m

c) 1080 turns/m

d) 104 turns/m

e) 472 turns/m

The winding density of the solenoid, n = 104 turns/m

Explanation:

Given that,

Length of the solenoid, l = 0.7 m

Radius of the circular cross section, r = 5 cm = 0.05 m

Energy stored in the solenoid,

Current, I = 0.4 A

To find,

The  winding density of the solenoid.

Solution,

The expression for the energy stored in the solenoid is given by :

Where

L is the self inductance of the solenoid

n is the winding density of the solenoid

n = 104 turns/m

So, the winding density of the solenoid is 104 turns/m

answer: electrons