Ashopper in a supermarket pushes a loaded 32kg cart with a horizontal force of 12 n. how far will the cart move in 3.5 seconds, starting from rest? (disregard friction)

2.297 m

Explanation:

Mass of the cart = 32 Kg.

Force applied to the cart = 12 N.

So, Applying the formula F = ma ,

We get , 12 = 32a

a = 0.375 m/    (acceleration of the cart due to the force applied)

Now , as we know that s = ut + a

Where u is the initial speed which is zero here,

So, s = (0.375)   (Since, time given is 3.5              

                                                                                      seconds)

s = 2.297 m

Thus, distance covered by the cart will be 2.297 m .

your answer would be fusion