Acomplete description of simple harmonic motion must take into account several physical quantities and various mathematical relations among them. this information is needed to solve oscillation problems of this type. the position of a 60 g oscillating mass is given by x(t)=(2.0cm)cos(10t), where t is in seconds. part adetermine the velocity at t=0.40s. express your answer in meters per second to two significant figures.

Velocity will be -0.0139 m/sec

Explanation:

We have given mass m = 60 gram = 0.06 kg

Equation of displacement

We have to find the velocity at t = 0.4 sec

We know that velocity is given by

So velocity

At t = 0.4 sec

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

mistakes are ok