Light of wavelength 687 nm is incident on a single slit 0.75 mm wide. at what distance from the slit should a screen be placed if the second dark fringe in the diffraction pattern is to be 1.7 mm from the center of the diffraction pattern? a) 0.39 m
b) 0.47 m
c) 0.93 m
d) 1.1 m
e) 1.9 m

D = 0.93 m

Explanation:

given,

wavelength of the light source (λ)= 687 nm

slits is separated (d) = 0.75 mm

distance to form interference pattern(D) =?

n = 2

now, using displacement formula

where y is the fringe width

y = 1.7 mm

     D = 927.95 mm

     D = 0.927 m

     D = 0.93 m

Hence, the correct answer is option C

pe = weightxheight = 2000x1000=2,000,000joules

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )