Acircular parallel-plate capacitor with a spacing of 1.6 mm is charged to produce a uniform electric field with a strength of 2.7 × 106 n/c. what plate radius is required if the stored charge is −1.07 µc? the permittivity of a vacuum is 8.8542 × 10−12 c2/n · m2. answer in units of m.

    r = 0.119 m

Explanation:

distance (d) = 1.6 mm = 0.0016 m

electric field strength (E) = 2.7 x 10^{6} N/C

charge (Q) = -1.07 μC = -1.07 x 10^{-6} C

permitivity of vacuum = 8.8542 x 10^{-12} C^{2}/N

find the radius of the plate required

        voltage (V) = E x d

        voltage (V) =  2.7 x 10^{6} x 0.0016 = 4320 V

        C =  -1.07 x 10^{-6} / 4320 = 2.47 x 10^{-10} F

        we can rearrange the equation above to have our area (A) = Cd/ E₀

         A =

         A = 0.0446 m^{2}

       r =

       r =

      r = 0.119 m

answer: i'm not sure which is which for i get confused on it all the time but i can tell you that the answer lies with the convex and concave devices. i hope this you. have a good day and best of luck to you!

explanation: