You will have a human eye model setup that consists of an eye hold, two options for a human lens, and an adjustable retina screen that will displace your light source in fine detail when the setup is focused properly. your light source consists of a light bulb box that you can slide toward and away from the eyeball, with a ruler where you can measure the exact distances between all parts in the setup. you will also have weaker lenses that you can use to try to fix problems that arise when the eyeball not at the right size to complement the lens power provided by the eye muscles.

in activity 2, you will explore the human eye model when the human eye is the correct length and the muscles in the eye can squish and relax the eye such that the eye power ranges from +7 or +8 diopters to +20 diopters (meaning the lens is converging with focal length ranging from 1/7 or ⅛ to 1/20 meters). describe your experimental setup that will contrast where the light source must be located to focus with 7 or 8 diopter lens, vs. where the light source must be located to focus with the 20 diopter lens.

Red’s momentum vector before the collision is green’s momentum vector after the collision. question 1 options: equal to shorter than longer than question 2 (1 point) saved since green bounces off red, this must be an collision. question 2 options: explosion elastic inelastic question 3 (1 point) red transfers of its momentum to green during the collision. question 3 options: none all little most question 4 (4 points) why does red transfer all its momentum to green? back up your answer with information from the simulation. write at least 2 sentences. question 4 options: skip toolbars for . more insert actions. more text actions. more paragraph style actions. question 5 (1 point) now make red much heavier than green. answer the questions below to describe how both red and green behave after the collision. question 5 options: slowed down sped up kept the same velocity question 6 (1 point) green sped up during the collision as it question 6 options: gained momentum from red lost momentum to red maintained a constant momentum. question 7 (1 point) after the collision . . question 7 options: both green and red moved to the right. both green and red stopped as they have lost all momentum. red stopped and green moved to the right. red bounced off green and went to the left. green moved to the right. question 8 (4 points) only some of red’s momentum was transferred to green. why did this occur? back up your answer with information from the simulation. write at least 2 sentences. question 8 options: skip toolbars for . more insert actions. more text actions. more paragraph style actions. question 9 (1 point) now make red much lighter than green. answer the questions below to describe how both red and green behave after the collision question 9 options: green sped up after the collision therefore it must have gained momentum. green sped up after the collision therefore it must have lost momentum. green slowed down after the collision therefore it must have gained momentum. green slowed down after the collision therefore it must have lost momentum. question 10 (1 point) since green gained momentum, red had to have momentum because you cannot create or destroy momentum. question 10 options: gained lost kept the same amount of question 11 (1 point) since green was so much and harder to move, it caused red to bounce back to the left giving red . question 11 options: heavier . . . . positive lighter. . . . negative lighter. . . . positive heavier . . . . negative question 12 (4 points) now, click on more data at the bottom of the sim. play with different numbers for the masses and starting velocities. you can even make the starting velocities negative! tell me one thing you discovered by adjusting the speeds and masses. write at least 2 sentences. be specific and use words like velocity, momentum, mass, increased, decreased, etc. 13. true or false: when red and green collide, they stick together. question 13 options: true false question 14 (1 point) the velocity of red & green after the collision is the velocity that red started off with. question 14 options: larger than smaller than equal to question 15 (1 point) the velocity after the collision was less because the mass has question 15 options: stayed the same decreased increased question 16 (1 point) the momentum before the collision was the momentum after the collision. question 16 options: larger than smaller than equal to conclusions question 17 (4 points) how are elastic and inelastic collisions different? give two or more ways. your answer should have at least 2 sentences. question 18 (4 points) give an example of a collision in real life. use the law of conservation of energy to describe the transfer of momentum. be sure and discuss the momentum before and after the collision occurs. you will need at least 3 sentences to thoroughly answer this question.

Amass m = 74 kg slides on a frictionless track that has a drop, followed by a loop-the-loop with radius r = 18.4 m and finally a flat straight section at the same height as the center of the loop (18.4 m off the ground). since the mass would not make it around the loop if released from the height of the top of the loop (do you know why? ) it must be released above the top of the loop-the-loop height. (assume the mass never leaves the smooth track at any point on its path.) 1. what is the minimum speed the block must have at the top of the loop to make it around the loop-the-loop without leaving the track? 2. what height above the ground must the mass begin to make it around the loop-the-loop? 3. if the mass has just enough speed to make it around the loop without leaving the track, what will its speed be at the bottom of the loop? 4. if the mass has just enough speed to make it around the loop without leaving the track, what is its speed at the final flat level (18.4 m off the ground)? 5. now a spring with spring constant k = 15600 n/m is used on the final flat surface to stop the mass. how far does the spring compress?

Assume that two of the electrons at the negative terminal have attached themselves to a nearby neutral atom. there is now a negative ion with a charge -2e at this terminal. what are the electric potential and electric potential energy of the negative ion relative to the electron? the electric potential and the electric potential energy are both twice as much. the electric potential is twice as much and the electric potential energy is the same. the electric potential is the same and the electric potential energy is twice as much. the electric potential and the electric potential energy are both the same. the electric potential is the same and the electric potential energy is increased by the mass ratio of the oxygen ion to the electron. the electric potential is twice as much and the electric potential energy is increased by the mass ratio of the oxygen ion to the electron.