For a home sound system, two small speakers are located 52 cm closer to the listener than the other. for what value of the fundamental frequency of audible sound will these speakers produce constructive interference at the listener? speed of sound is 344 m/s

661.54 Hz

Explanation:

The lowest frequency (n=1) for the constructive interference is known as the fundamental frequency. For constructive interference, the difference in the distances of the speakers from the observer is equivalent to the multiple of the wavelength. Thus:

For fundamental frequency, the wavelength = 0.52/1  = 0.52 m

We know that: V = f*λ

V = speed of sound = 344 m/s

f = fundamental frequency = ?

λ = wavelength = 0.52 m

f = V/λ = 344/0.52 = 661.54 Hz

the velocity you are looking for is made up of two parts: horizontally velocity, vh, and its vertical velocity, vv. the actual velocity of the ball will be these two parts added together, and because velocity is a vector then they will need to be added vectorially.  

neglecting air resistance etc etc.,  

the horizontal velocity component will be constant (because there is no accelerating force in the horizontal direction.  

vh = 8 ms-1  

the vertical velocity component has an accelerating force: 'g'.  

using v = u +at where a = g = 9.81 ms-2.  

the vertical component of velocity, vv = 0 + gt = vv =9.81 x 2  

vv = 19.62 ms-1 . the zero appears because the virtical component of velocity at time t=0 is zero. remember, the ball was thrown horizontally.  

how fast it will be moving (it actual path (being a parabola )) will be the vector sum of these two.  

adding vectorally gives: -  

v = sqr root (8^2 + 19.62^2) = sqr root(64+384.9) = 21.18 or 21.2 ms-1

i dont know but

explanation:

whoever your teacher is, deserves a raise for using pokemon as an example