The horsepower (hp) that a shaft can safely transmit varies jointly with its speed (in revolutions per minute, rpm) and the cube of its diameter. if a shaft of a certain material 2 inches in diameter can transmit 36 hp at 75 rpm, what diameter must the shaft have in order to transmit 375 hp at 50 rpm?

d = 5 inch

Explanation:

First to all we need to get the expression to calculate the horsepower.

The expression to use is the following:

hp = k * v * d³ (1)

Where:

hp: horsepower

v: speed (in rpm)

d: diameter

k: constant of horsepower.

The value of k, because is a constant, will be the same when the shaft is transmiting 375 hp at 50 rpm. So, with the first data, we can calculate the value of k, and then, the value of the diameter

Solving for k in (1) we have:

k = hp / v * d³

replacing the data:

k = 36 / 75 * 2³

k = 0.06

With this value, we can solve for d and we have:

d = ∛hp / k * v

d = ∛375 / 50 * 0.06

d = 5 inch

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.