Suppose the b string on a guitar is 24" long and vibrates with a frequency of about 247 hz. you place your finger on the 5th fret, which changes the length of the string to 18". which note do you hear when you play the string d (about 294 hz) o e (about 329 hz) og (about 392 hz)

To solve this problem it is necessary to apply the related concepts to string vibration. This concept shows the fundamental frequency of a string due to speed and length, that is,

Where

v = Velocity

L = Length

Directly if the speed is maintained the frequency is inversely proportional to the Length:

Therefore the relationship between two frequencies can be described as

Our values are given as,

Therefore the second frequency is

The frequency allocation of 329Hz is note E.

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.

answera compound;