The flowers of the bunchberry plant open with astonishing force and speed, with pollen grains accelerating from rest to 7.5 m/s. a. what impulse is delivered to a 1.0 * 10-10 kg pollen grain? b. what is the average force if this impulse is delivered in 0.30 ms? c. how does this force compare to the weight of the pollen grain?

a)  I = 7.5 10⁻¹⁰ N s , b)  F = 25 10⁻¹⁰ N , c)  F / W = 2.55

Explanation:

a) The momentum is related to the moment by the equation

       I = F t = Δp

       I = m v - m v₀

In our case the initial speed is zero, let's calculate}

       I = m v -0

       I = 1.0 10⁻¹⁰ 7.5

       I = 7.5 10⁻¹⁰ N s

b) the average force

       F t = mv

       F = mv / t

Let's calculate

       F = 1.0 10⁻¹⁰ 7.5 / 0.30

       F = 25 10⁻¹⁰ N

The weight of a pollen grain is

      W =m g

      W = 1.0 10⁻¹⁰ 9.8

      W = 9.8 10⁻¹⁰

The relationship between the two is

      F / W = 25 / 9.8

      F / W = 2.55

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