Acamera lens in air (index 1.00) is coated with a thin film with a thickness l that maximizes the transmitted light (and minimizes the reflected light) for a particular wavelength. if the thin film has an index of 1.25 and the lens material an index of 1.50, what minimum thickness l is required? (let λn be the wavelength in the thin film.)

t = 100 nm

Explanation:

given,

Refractive index of coating is n ' = 1.25

refractive index of glass is n = 1.5

assuming wavelength of the film = 500 nm

destructive interference is

for minimum thickness m = 0

      t = 100 nm

hence, the minimum thickness required is t = 100 nm

a person with a mass of 106kg has a weight of 1060n

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .