What is the value of the magnetic field at a distance r = 6.50 cm from the axis of the conducting tube? recall that μ0=4π×10−7 t⋅m/a. express your answer numerically in teslas.

all of the answers are correct.

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energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j