Pendulum swing. you pull a simple pendulum that is 0.240 m long to the side through an angle 3.5◦ and release it.
(a) how much time does it take the pendulum bob to reach its highest speed?
(b) how much time does it take if the pendulum is released at an angle of 1.75◦ instead?

The 'period' of a pendulum . . . the time it takes to go back and forth once, and return to where it started . . . is

T = 2π √(length/gravity)

For this pendulum,

T = 2π √(0.24m / 9.8 m/s²)

T = 2π √0.1565 s²

T = 0.983 second

If you pull it to the side and let it go, it hits its highest speed at the BOTTOM of the swing, where all the potential energy you gave it has turned to kinetic energy.  That's 1/4 of the way through a full back-and-forth cycle.

For this pendulum, that'll be (0.983s / 4) =

(A). T = 0.246 second   <===

Notice that the formula T = 2π √(length/gravity) doesn't say anything about how far the pendulum is swinging.  For small angles, it doesn't make any difference how far you pull it before you let it go . . . the period will be the same for tiny swings, little swings, and small swings.  It doesn't change if you don't pull it away too far.  So . . .

(B).  The period is the same whether you pulled it 3.5 or 1.75 . T = 0.246 s.  

you have to draw the persons position over there

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2