Abody moving with an initial velocity of 30m/s accelerates uniformly at the rate of 10m/s . what is the distance covered during the period

The distance covered by the body is, S = 800 m

Explanation:

Given data,

The initial velocity of the body, u = 30 m/s

The acceleration of the body, a = 10 m/s²

Let the time period of travel be, t = 10 s

Using the II equations of motion,

                       S = ut + ½ at²

Substituting the given values,

                        S = 30 x 10 + ½ x 10 x 10²

                         S = 800 m

Hence, the distance covered by the body is, S = 800 m

ok

explanation:

490 n

f=125n a=2.5m/s2