Two equal masses are attached to separate identical springs next to one another. one mass is pulled so its spring stretches 20 cm and the other is pulled so its spring stretches only 10 cm. the masses are released simultaneously. which mass reaches the equilibrium point first?

Both reaches equilibrium simultaneously.

Explanation:

Given that,

First stretch spring= 20 cm

Second stretch spring = 10 cm

Two equal masses are suspended from identical spring.

Their forces constants are equal time period for oscillation

Using formula of time period

Where, T = time period

m = mass

k = spring constant

Time period independent of amplitude.

Hence, Both reaches equilibrium simultaneously.

b) phosphorus pentoxide

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.