![Ek=Ep\\where:\\Ek=kinetic energy [J]\\Ep=potencial energy [J]](/tpl/images/0417/6618/7a528.png)
![Ep=m*g*h\\where:\\m=mass of the ball[kg}\\g=gravity[m/s^2]\\h=heigth [m]\\](/tpl/images/0417/6618/51191.png)
![Ek=\frac{1}{2}*m*v_{0} ^{2} \\where\\v_{0} = initial velocity[m/s]](/tpl/images/0417/6618/2acc2.png)
![Ek=Ep\\\frac{1}{2} *m*v_{0} ^{2} =m*9.81*h\\h=\frac{40^{2}}{2*9.81} \\h=81.5[m]](/tpl/images/0417/6618/e9802.png)
3. a ball is thrown straight up with an initial velocity of 40 m/s.
a. what is its velocity at...
Physics, 13.12.2019 22:31 brusierlover8590
3. a ball is thrown straight up with an initial velocity of 40 m/s.
a. what is its velocity at the top of its path?
Answers: 2
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