An airliner arrives at the terminal, and the engines are shut off. the rotor of one of the engines has an initial clockwise angular velocity of 2000 rad/s. the engine’s rotation slows with an angular acceleration of magnitude 80.0 rad/s2. (a)determine the angular velocity after 10.0 s. (b) how long does it take the rotor to come to rest?

(a) ωf = 1200 rad/s

(b) t  = 25 s

Explanation:

Kinematic Equation to the rotor

ωf= ω₀ + α*t  Formula (1)

Where:

α : angular acceleration (rad/s²)

t : time interval (s)

ω₀ : initial angular velocity ( rad/s)

ωf : final angular velocity  ( rad/s)

(a) Angular velocity after 10.0 s

Data

α = -80 rad/s²

t = 10 s

ω₀ = 2000 rad/s

We apply the formula (1):

ωf = ω₀ - α*t

ωf = 2000 -  80*(10)

ωf = 2000 - 800

ωf = 1200 rad/s

(b) Time the rotor stops

Data

α = -80 rad/s²

ω₀ = 2000 rad/s

ωf = 0

We apply the formula (1):

ωf = ω₀ - α*t

0 = 2000 -  80*(t)

80*(t) = 2000

t = 2000 / 80

t  = 25 s

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this