The filament of a certain lamp has a resistance that increases linearly with temperature. when a constant voltage is switched on, the initial current decreases until the filament reaches its steady-state temperature. the temperature coefficient of resistivity of the filament is 43 times 10^-3 k^-1. the final current through the filament is one- eighth the initial current. what is the change in temperature of the filament?

a.30100 k
b.378 k
c.1627 k
d.814 k
e.1162 k

162.8 K

Explanation:

initial current = io

final current, i = io/8

Let the potential difference is V.

coefficient of resistivity, α = 43 x 10^-3 /K

Let the resistance is R and the final resistance is Ro.

The resistance varies with temperature

R = Ro ( 1 + α ΔT)

V/i = V/io (1 + α ΔT )

8 = 1 + 43 x 10^-3 x ΔT

7 = 43 x 10^-3 x ΔT

ΔT = 162.8 K

Thus, the rise in temperature is 162.8 K.

the answer to your question is high voltage and high currency

tube or goog will be great resources to find the answer to the question that you're asking