Many species cool themselves by sweating, because as the sweat evaporates, heat is transferred to the surroundings. a human exercising strenuously has an evaporative heat loss rate of about 657 w. if a person exercises strenuously for 28.6 min, how much water must he drink to replenish his fluid loss? the heat of vaporization of water is 2430 j/g at normal skin temperature.

The water lost is 463.95 g.

Explanation:

Given that,

Heat lost rate = 657 W

Time = 28.6 min

Heat vaporization = 2430 J/g

We need to calculate the heat lost

Using formula of heat loss

We need to calculate the water lost

Using formula of water lost

Put the value into the formula

Hence, The water lost is 463.95 g.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s