Physics, 16.12.2019 18:31 wendelkristen
Water is being drained from a container which has the shape of an inverted right circular cone. the container has a radius of 7.00 inches at the top and a height of 9.00 inches. at the instant when the water in the container is 8.00 inches deep, the surface level is falling at a rate of 1.4 in./sec. find the rate at which water is being drained from the container.
Answers: 2
![\frac{\mathrm{d} V}{\mathrm{d} t}=\frac{\pi }{3}\left [ 2r\frac{\mathrm{d} r}{\mathrm{d} t}\cdot h+\frac{\mathrm{d} h}{\mathrm{d} t}\cdot r^2\right ]](/tpl/images/0420/8286/9d591.png)
![\frac{\mathrm{d} V}{\mathrm{d} t}=\frac{\pi }{3}\left [ 2\times 6.22\times 1.08+1.4\times 6.22^2\right ]](/tpl/images/0420/8286/ddad7.png)
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Water is being drained from a container which has the shape of an inverted right circular cone. the...
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