Water, with a density of rho = 1145 kg/m 3 , flows in a horizontal pipe. in one segment of the pipe, the flow speed is v 1 = 7.33 m/s . in a second segment, the flow speed is v 2 = 1.57 m/s . what is the difference between the pressure in the second segment ( p 2 ) and the pressure in the first segment ( p 1 )?

the pressure difference will be ΔP= P₂ - P₁ =29348.64 Pa

Explanation:

from Bernoulli's equation

P₁ + ρgh₁+ 1/2ρv₁²= P₂ + ρgh₂+1/2ρv₂²

where P = pressure , ρ= density , g= gravity , h= height , v=flow speed and 1 and 2 denote first and second segment respectively

then since the pipe is horizontal there is no difference in height (h=h₁=h₂) , thus

P₁ + 1/2ρv₁²= P₂ + 1/2ρv₂²

the pressure difference ΔP= P₂ - P₁  will be

ΔP= P₂ - P₁ = 1/2ρv₁² - 1/2ρv₂² = 1/2*ρ* (v₁² - v₂²)

replacing values

ΔP= 1/2*ρ* (v₁² - v₂²) = 1/2 *1145 kg/m³ * [(7.33 m/s)² - (1.57 m/s)²] = 29348.64 Pa

ΔP= 29348.64 Pa

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.