The blades of a ceiling fan have a radius of 0.380 m and are rotating about a fixed axis with an angular velocity of +1.50 rad/s. when the switch on the fan is turned to a higher speed, the blades acquire an angular acceleration of +2.00 rad/s². after 0.500 s has elapsed since the switch was reset, what is (a) the total acceleration (in m/s²) of a point on the tip of a blade and (b) the angle ϕ between the total acceleration → a and the centripetal acceleration → a c ?

(A) 4.75 m/s^{2}

(b) 81.5°

Explanation:

radius (r) = 0.38 m

initial angular velocity (ω') = 1.5 rad/s

angular acceleration (α) = 2 rad/s^{2}

time (t) = 0.5 s

(A)   tangential acceleration (a) = α x r

       a = 2 x 0.38 = 0.76 rad/s^{2}

       final angular velocity (ω) = ω + αt

       ω = 1.5 + (2 x 0.5) = 3.5 m/s

       a' = = 4.7 m/s^{2}

       total acceleration = = 4.75 m/s^{2}

(B)  tanθ

      θ=

      θ= = 81.5°

protons in

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.