Suppose that on a hot and sticky afternoon in the spring, a tornado passes over the high school. if the air pressure in the lab (volume of 180m3) was 1.1 atm before the storm and 0.85 atm during the storm, to what volume would the laboratory try to expand in order to make up for the large pressure difference outside?

a. 190m3
b. 230m3
c. 1,800m3
d. 7,100m3

232.9m³ (Option b. is the closest answer)

Explanation:

Given:

Air pressure in the lab before the storm, P₁ = 1.1atm

Air volume in the lab before the storm, V₁ = 180m³

Air pressure in the lab during the storm P₂ = 0.85atm

Air volume in the lab before the storm, V₂ = ?

Applying Boyle's law:    P₁V₁ = P₂V₂    (at constant temperature)

                           V₂  = 232.9m³

The air volume in the laboratory that would expand in order to make up for the large pressure difference outside is 232.9m³

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.