6. you are in an airplane going down a runway currently going 24 m/s and accelerating at 8 m/s?
for 800 m until takeoff. how long does it take the plane to go those 800 m?

The time taken by the airplane to take off, t = 11.46 s

Explanation:

Given data,

The initial velocity of the airplane, u = 24 m/s

The acceleration of the plane, a = 8 m/s

The distance covered until take off, d = 800 m

Using the III equation of motion,

                      v² = u² +2as

                           = 24² + 2 x 8 x 800

                           = 13376

                       v = 115.65 m/s

Using the first equation of motion,

                      v = u + at

                       t = (v-u) / a

                         = (115.65 - 24) / 8

                         = 11.46 s

Hence, the time taken by the airplane to take off, t = 11.46 s

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray