You have a 200 ω resistor, a 0.400 h inductor, a 6.00 μf capacitor and a voltage source that has a voltage amplitude of 30.0 v and an angular frequency of 250 rad/s. the resistor, inductor, capacitor, and voltage source are connected to form an l-r-c series circuit. the current is given by i=icos(ωt), so v=vcos (ωt φ). what is v at t = 20ms? what is vr at t = 20ms? what is vc at t = 20ms? what is vl at t = 20ms? what is v at t = 40ms? what is vr at t = 40ms? what is vc at t = 40ms? what is vl at t = 40ms?

That depends on what kind of environ meant it is in  in space it has the same force that was applied when the velocity was gained

Letter a, because when there are unlike charges they will always attract to each other.

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s