Apoint charge with charge q1 = 2.10 μc is held stationary at the origin. a second point charge with charge q2 = -4.70 μc moves from the point ( 0.105 m , 0) to the point ( 0.290 m , 0.245 m ). how much work w is done by the electric force on the moving point charge?

0.613 J

Explanation:

charge q1 = 2.10 μC =

charge q2 = -4.70 μC =

location of q1 = (0,0)

initial location of q2 = (0.105m , 0)

final location of q2 =  (0.290m , 0.245m )

find the work done by the electric forces on the moving point charge

work done = kq1q2()

where

work done =  

work done = -88 x 10^{-3} x -6.9 = 0.613 J

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm