The motor driving a grinding wheel with a rotational inertia of 0.36 kg m2 is switched o? when the wheel has a rotational speed of 25 rad/s. after 6.6 s, the wheel has slowed down to 20 rad/s. what is the absolute value of the constant torque exerted by friction to slow the wheel down? answer in units of nm.

Torque will be 0.2727 N -m

Explanation:

We have given rotational inertia of the motor

Initial angular speed 25 rad/sec

Final angular speed = 20 rad/sec

Time to change in speed t = 6.6 sec

From first equation of motion

Now torque

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explanation:

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