Suppose you warm up 510 grams of water (about half a liter, or about a pint) on a stove, and while this is happerning, you also stir the water with a beater, doing 6 x 104 j of work on the water. after the large-scale motion of the water has dissipated away, the temperature of the water is observed to have risen from 18°c to 82°c

part 1 (a) what was the change in the thermal energy of the water? aethermal = the tolerance is +/-5% attempts: 0 of 10 used *

part 2 (b) taking the water as the system, how much energy transfer due to a temperature difference (microscopic work) q was there across the system boundary? j the tolerance is +/-5% attempts: 0 of 10 used

part 3 (c) taking the water as the system, what was the energy change of the surroundings? aesurtoundings the tolerance is +/-5% attempts: 0 of 10 used

he kicked it 10 feet straight up into the air? i think this works.

heats surface water up

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.

this would be about 43%