Au-tube is filled with water until the liquid level is 28cm above the bottom of the tube. an oil of specific gravity 0.78 is now poured into one arm of the u-tube until the level of the water in the other arm of the tube is 34 cm above the bottom of the tube. find the level of the oil-water and oil-air interfaces in the other arm of the tube.

Answer

given,

height of water = 28 cm

specific gravity of the oil = 0.78

new height of the water level = 34 cm

height of water = ?

increase in height = 34 - 28 = 6 cm

water oil interface is at = 28 - 6 = 22 cm

so, now, 12 cm of weight of water is to be displaced by oil

height of the equivalent oil

      = 12 / 0.78

      = 15.38 cm

height of the oil from the bottom is equal to

     = 22 + 15.38

     = 37.38 cm

nah.   i'm just sleepy.

it is given that trillions of microbes make up to 1% to 3% of the body mass.

let's take average of this percentage: 2%

consider the average mass of the human body as 70 kg.

then, trillions of microbes would have mass  

therefore, 100 trillion micro-organisms would weigh:

this is an approximate value and could change depending on the mass of the human body and percentage of the microbes present in it.

average mass per microorganism =