In the plant arabidopsis thaliana, a geneticist is interested in the development of trichomes (small projections). a large screen turns up two mutant plants (a and b) that have no trichomes, and these mutants seem to be potentially useful in studying trichome development. (if they were determined by single-gene mutations, then finding the normal and abnormal functions of these genes would be instructive.) each plant is crossed with wild type; in both cases, the next generation (f1) had normal trichomes. when f1 plants were selfed, the resulting f2's were as follows: f2 from mutant a: 602 normal; 198 no trichomes f2 from mutant b: 267 normal; 93 no trichomes what can be deduced about the trichome mutants?

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

Attach the free body diagram and i will you answer the question.! : d

Phagocytes contain digestive enzymes to facilitate the process of phagocytosis