An electromagnetic wave has a frequency of and is traveling in a vacuum. the magnetic field is given by

(a) find the wavelength and the direction of propagation of this wave.
(b) find the electric field vector.
(c) determine the poynting vector, and use it to find the intensity of the wave.

c) true. With the magnetic field you can determine the Poynting vector and this is equal to the intensity of the wave

Explanation:

An electromagnetic wave carries energy that is given by the vector of poyntíng

     S = 1 / μ₀ E x B

The electric and magnetic fields are related

     E = c B

Substituting

     S = c /μ₀ B² / 2

The two comes from the average value

Let's examine the claims

a) false to determine the wavelength the frequency is needed

b) False. To find the electric field you need the magnetic field

c) true. With the magnetic field you can determine the Poynting vector and this is equal to the intensity of the wave

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft