The small piston of a hydraulic lift has a diameter of 8.0 cm, and its large piston has a diameter of 40cm. the lift raises a load of 15,000n.
a) determine the force that must be applied to the small piston.
b) determine the pressure applied to the fluid in the lift.

Part a)

F = 600 N

Part b)

P = 119366.20 Pascal

Explanation:

Part a)

As we know that by Pascal's law pressure must be transmitted through out the liquid without any change

So pressure at bigger piston = pressure at smaller piston

now by solving above equation we have

Part b)

Pressure applied at fluid is given as

P = 119366.20 Pascal

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

come closer and become far apart and become steam/gas