Astudent measures the maximum speed of a block undergoing simple harmonic oscillations of amplitude a on the end of a single ideal spring with spring constant k. the single spring is then replaced with 3 identical springs (in series) with the same spring constant k. if the same block undergoes shm with the same amplitude before, by what factor does the maximum speed change?

Explanation:

Given

Amplitude of oscillation is A

spring constant k

suppose m is the mass of block so its natural frequency of oscillation is given by

When three identical springs is connected in series

Natural Frequency becomes

Thus maximum speed with Amplitude A is

so by a factor of maximum velocity is changed      

it would be kevlar ^^

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s