The predictions of rutherford's scattering formula failed to correspond with experimental data when the energy of the incoming alpha particles exceeded 32mev. this can be explained by the fact that the predictions of the formula apply when the only force involved is the electromagnetic force and will break down if the incoming particles make contact with the nucleus. use the fact that rutherford's prediction ceases to be valid for alpha particles with an energy greater than 32mev to estimate the radius r of the gold nucleus. i am doing something really silly. i keep getting 7.43*10^-31 which is off by a factor of 16. i need a detailed explaination so i can find out where i went wrong. i equated the ke = 5.12e-12 = k(79e^2/r)

Alivestock company reports that the mean weight of a group of young steers is 1100 pounds with a standard deviation of 93 pounds. based on the model n(1100,93) for the weights of steers, what percent of steers weigh a) over 1050 pounds? b) under 1300 pounds? c) between 1150 and 1250 pounds?

Scientists use laser range-finding to measure the distance to the moon with great accuracy. a brief laser pulse is fired at the moon, then the time interval is measured until the "echo" is seen by a telescope. a laser beam spreads out as it travels because it diffracts through a circular exit as it leaves the laser. in order for the reflected light to be bright enough to detect, the laser spot on the moon must be no more than 1.0 km in diameter. staying within this diameter is accomplished by using a special large-diameter laser. part a if λ = 540nm , what is the minimum diameter of the circular opening from which the laser beam emerges? the earth-moon distance is 384,000 km. express your answer to two significant figures and include the appropriate units.

Will you chech and finish these for me, because i am stumped with them.