The planet xyz traveling about the star abc in a circular orbit takes 24 hours to make an orbit. assume that the orbit is a circle with radius 89 comma 000 comma 00089,000,000 mi. find the linear speed of xyz in miles per hour.

v = 2.33 10⁷ mi / h

Explanation:

For this exercise we must observe that the velocity module is constant, so we can use the kinematic relation

       v = d / t

The distance traveled in each orbit is the length of the circle

      L = 2π r

The time it takes in orbit is called period (T)

Let's reduce the quantities

      r = 8.9 10⁷ mi

      t = 24 h (3600s / 1 h) = 86400 s

We replace

      v = 2π r / T

Let's calculate

     v = 2π 8.9 10⁷/86400

     v = 6.47 10³ mi / s

     v = 6.47 10³ mi / s (3600 s / 1h)

     v = 2.33 10⁷ mi / h

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force