Acar traveling 56.0 km/h is 24.0 m from a barrier when the driver slams on the brakes. the car hits the barrier 2.00 s later. (a) what is the magnitude of the car’s constant acceleration before impact? (b) how fast is the car traveling at impact?

(A) acceleration = -3.6m/s². This is deceleration or negative acceleration.

(B) Therefore, velocity just before impact, v = 8.4m/s

Explanation:

(a) Initial velocity, u = 56km/h = (56*1000/3600)m/s = 15.6m/s

Distance, s = 24.0m, time, t = 2.0s, acceleration, a = ?

Using the equation, s = ut + 1/2at²

24.0m = 15.6m/s * 2s + (a * 2²)/2

24.0 = 31.2 +2a

2a = -31.2 + 24

2a = -7.2

a = -7.2/2

acceleration = -3.6m/s². This is deceleration or negative acceleration.

(b) final velocity just before impact, v = ? initial velocity, u = 15.6m/s, acceleration = -3.6m/s², time, t = 2.0s

using the equation v = u + at

v = 15.6m/s + (-3.6m/s² * 2s)

v = 15.6m/s - 7.2m/s

v = 8.4m/s

Therefore, velocity just before impact, v = 8.4m/s

weather forecasts are done by collecting data about the current state of the atmosphere mainly the temperature, humidity and wind and using meteorology, to determine the atmosphere that evolves over time. the h and l mean the high and low pressure. the red strip is a warm front. the blue strip is a cold front. the blue and red strip is a stationary front. the purple strip is a occluded front.

explanation:

a electromagnetic waves