Two identical mandolin strings under 200 n of tension are sounding tones with frequencies of 590 hz. the peg of one string slips slightly, and the tension in it drops to 192 n. how many beats per second are heard?

To solve this problem it is necessary to apply the concepts related to frequency and vibration of strings. Mathematically the frequency can be expressed as

Then the relation between two different frequencies with same wavelength would be

The beat frequency heard when the two strings are sounded simultaneously is

We have the velocity of the transverse waves in stretched string as

And,

Therefore the relation between the two is,

Finally substituting this value at the frequency beat equation we have

Therefore the beats per second are 11.92Hz

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