Abullet of mass 0.037 kg is fired horizontally with a speed of 77 m/s from a tall bridge. if the bullet is in the air for 2.1 s. how far from the base of the bridge does it land in m?

Starting from the assumption that for the time traveled, the bullet has no loss in its speed and considering the cinematic equations of movement description we have to

Where,

x = Displacement

t = Time

Replacing with our values and rearranging to find the displacement we have

The distance from the base of the bridge where it lands is 161.7m

their crystal patterns have been disrupted by stress