The hubble space telescope orbits the earth at an approximate altitude of 612 km. its mass is 11,100 kg and the mass of the earth is 5.97×1024 kg. the earth's average radius is 6.38×106 m. what is the magnitude of the gravitational force that the earth exerts on the hubble?

magnitude of the gravitational force is 9.04 × N

Explanation:

given data

altitude = A = 612 km = 612000 m

mass M = 11,100 kg

mass of the Earth m = 5.97 × kg

Earth average radius = 6.38 ×  m

to find out

magnitude of the gravitational force

solution

first we get here distance from space to centre of earth that is

distance = altitude + earth radius

distance = 612000  +  6.38 ×  m

distance = 6.99 ×  m  

so now we get here  magnitude of the gravitational force that is express as

magnitude of the gravitational force F =   ...........1

here G is gravitational constant  that is 6.67 × Nm² /kg and M is mass of space and m is mass of earth

put here all value we get

F =

F =

F = 9.04 × N

so magnitude of the gravitational force is 9.04 × N

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