Acar traveling with velocity v is decelerated by a constant acceleration of magnitude a. it travels a distance d before coming to rest. if its initial velocity were doubled, the distance required to stop would a) double as well. b) decrease by a factor of two. c) stay the same. d) quadruple.

D) quadruple.

Explanation:

Assuming the same constant acceleration a in both cases, as we have as givens  the acceleration a, the distance d, and the initial velocity v, we can use the following kinematic equations in order to compare the distances:

vf² - v₀² = 2*a*d

As the final state of the car is at rest, the final velocity vf, is 0.

⇒ - v₀² = 2*(-a)*d ⇒ d =v₀² / 2*a

1) initial velocity v₀

d₁ = v₀² / 2 a

2 ) initial velocity 2*v₀

⇒ d₂ = (2*v₀)² / 2*a = 4*v₀² / 2*a ⇒ d₂ = 4* (v₀² / 2*a)

⇒ d₂ = 4* d₁

As the equation shows, the distance required to stop, if the initial velocity were doubled, the distance required to stop would quadruple.

a cold ice-tea.

pour in room temperature or cold water. cover the pitcher and refrigerate. steep white or green tea for 6 to 8 hours; steep black or oolong tea for 8 to 12 hours.jun 28, 2015

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j