An object that weighs 2.450 n is attached to an ideal massless spring and undergoes simple harmonic oscillations with a period of 0.640 s. what is the spring constant of the spring?

a) 24.1 n/m
b) 2.45 n/m
c) 0.102 n/m
d) 12.1 n/m
e) 0.610 n/m

Spring constant, k = 24.1 N/m

Explanation:

Given that,

Weight of the object, W = 2.45 N

Time period of oscillation of simple harmonic motion, T = 0.64 s

To find,

Spring constant of the spring.

Solution,

In case of simple harmonic motion, the time period of oscillation is given by :

m is the mass of object

m = 0.25 kg

k = 24.09 N/m

or

k = 24.11 N/m

So, the spring constant of the spring is 24.1 N/m.

50 inches should be the resultant vector

v 154.9= 0.9 length length s little over 154.9cm