:the truck is to be towed using two ropes. determine the magnitudes of forces fa and fb acting on each rope in order to develop a resultant force of 950 n directed along the positive x axis. set θ = 50°.

Fa=774 N

Fb=346 N

Explanation:

We will solve this problem by equating forces on each axis.

While towing we know that car is mot moving in y-direction so net force in y-axis must be zero

⇒∑Fy=0

⇒

⇒

⇒

Given that resultant force on car is 950N in positive x-direction

⇒∑Fx=950  

⇒

⇒

⇒

⇒

⇒

⇒

⇒

Therefore approximately, Fa=774 N and Fb=346 N

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s