If 2.00 moles of lithium bromide are dissolved in 1000.0 grams of water at 25.0 °c, what is the final temperature of the water, assuming that all solutions have the same heat capacity as pure water (4.184 j/g-k)?

Explanation:

The dissociation of lithium bromide is given by the thermochemical equation as,

Number of moles, n = 2 moles

Molar mass of Lithium bromide is 86.845 g/mol

For the two moles, the heat released is,

For 2 moles of Lithium Bromide,

Initial temperature,

The heat capacity is given by :

is the final temperature

So, the final temperature of the water is 432.38 k. Hence, this is the required solution.

i would say