A3.2 kg particle starts from rest at x = 0 and moves under the influence of a single force fx = 4 + 15.7 x − 1.5 x 2 , where fx is in newtons and x is in meters. find the work done by this force on the particle as the particle moves from x = 0 m to x = 1.3 m. answer in units of j.

Explanation:

Work: This can be defined as the product of force and distance. The unit of work is Joules (J). it can be expressed mathematically as

W = F×d

or

W = .................................. Equation 1

Where b = upper limit, a = lower limit, Fx = expression of force.

Given: a = 0 , b = 1.3 m, Fx = 4 + 15.7x - 1.5x²

Substituting these values into equation 1

W =

W = ᵇ[4x + 15.7x²/2-1.5x³/3 +C]ₐ

Work = upper limit - lower limit

Work = ᵃ[4x + 15.7x²/2 - 1.5x³/3 +C] - [4x + 15.7x²/2 + 1.5x³/3 +C]ᵇ............... Equation 2

Substituting the values of a and b into equation 2

Work = [4(1.3) + 15.7(1.3)²/2-1.5(1.3)³/3 + C] - [0 +C]

Work = [5.2 + 26.53 -3.29 + C] - C

Work = 28.44 J

Work done by the force = 28.44 J.

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c. magnitude and direction